A force results from an interaction of two things (ball/Earth or ball/floor) and acts on an object. Objects do not have or possess or carry force. If the ball (which has a constant force when it hits the ground (X)) experiences the same constant force in the opposite direction (−X, minus indicating opposite direction), then the total force acting on the ball should be net ZERO ( X+(−X)=0).
Second, Newton's 3rd Law (N3L) is always in effect the ball is pulling on the Earth while the ball falls. Now when the ball makes contact with the ground, Newtons 3'rd Law takes effectįirst, $X=mg$, force of Earth's mass pulling on the ball. Moves to the ground with a constant force of say (X).
Shouldn't the ball just stay on the ground? Bouncing back means a force greater than (-X) was applied to the ball giving it upward motion. So there are no net forces acting on the ball, so why does it BOUNCE BACK? What am I missing? If the ball (which has a constant force when it hits the ground ( $X$)) experiences the same constant force in the opposite direction ( $-X$, minus indicating opposite direction), then the total force acting on the ball should be net ZERO ( $X + (-X) = 0$). If object A (the ball) exerts a force on object B (the floor), then object B will exert an equal force on object A in the opposite direction. Now when the ball makes contact with the ground, Newtons 3'rd Law takes effect (no air resistance): Gravity acts and this ball as it has mass and then the ball now moves to the ground with a constant force of say ( $X$).
Take a ball that's been dropped to the ground.
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